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5b^2-116=-9b
We move all terms to the left:
5b^2-116-(-9b)=0
We get rid of parentheses
5b^2+9b-116=0
a = 5; b = 9; c = -116;
Δ = b2-4ac
Δ = 92-4·5·(-116)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-49}{2*5}=\frac{-58}{10} =-5+4/5 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+49}{2*5}=\frac{40}{10} =4 $
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